(1/3)^(2x-3)=5

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Solution for (1/3)^(2x-3)=5 equation: 



(1/3)^(2x-3)=5

We move all terms to the left:

(1/3)^(2x-3)-(5)=0



Domain of the equation: 3)^(2x-3)!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)^(2x-3)-5=0

We multiply all the terms by the denominator


(+1-5*3)^(2x-3)=0

We add all the numbers together, and all the variables

(-14)^(2x-3)=0

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